Why Is the Speed of Light Ignored When Calculating the Distance of Lightning?

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When calculating the distance to a lightning strike, the speed of light is often ignored because its travel time is negligible compared to the time it takes for sound to reach the observer. In this case, the clap of thunder was heard 16.2 seconds after seeing the lightning, and using the speed of sound (343 m/s) yields a distance of approximately 5556.6 meters. The difference in time for light to travel that distance is only about 18.5 microseconds, which is insignificant for practical calculations. Variations in the speed of sound due to environmental factors can have a more substantial impact on accuracy. Therefore, for the precision implied by the time measurement, the speed of light can be considered inconsequential.
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Homework Statement



suppose you hear a clap of thunder 16.2s after seeing the associated lightning stroke. The speed of sound waves in air is 343 m/s and the speed of light in air is 3.00E8 m/s. How far are you from the lightning stroke?

Homework Equations



5556.6m is the correct answer, however, why is the speed of light in air ignored?

The Attempt at a Solution


v=\frac{d}{t}
d=V*T
343 m/s * 16.2s=5556.6m
 
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Its ignored because the difference is too small. You can assume that the instant you saw the light is the instant the thunder clap took place.
 
Thanks! it now makes sense:blushing:
 
299,792,458 m/s
 
Yes unscientific, that IS how fast I can run :-p

Not only is the difference between the actual thunder clap and seeing the lightning so insignificantly small (18.5 microseconds), the variations in the speed of sound in air can alter the true results quite more significantly. Rain/wind etc. can all factor into the speeds.
 
If d is the distance,in meters, from the lighting to you, it would take the light d/c= (d/3)*10^-8 seconds to reach you. It would take the sound d/s= d/343 seconds to reach you. If you hear the sound 16.2 seconds after seeing the light, you know that d/343- (d/3)*10^-8= 16.2 Multiplying both sides by 343 and 3*10^8, 3(10^8)d- 343d= 1666980000000 or (300000000- 343)d= 299999657d= 1666980000000. d= 1666980000000/299999657= 5556.60635305 meters. Since the original time was only measured to three significant figures, that is no more accurate than 5560 meters.

Essentially, saying the time was "16.2 seconds" implies you are measuring to the nearest tenth of a second. Since it takes light much less than .1 second to reach you, to that accuracy, the time it takes the light to reach you is neglible.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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