Why is the unit normal of a sphere important in vector calculations?

AI Thread Summary
The discussion focuses on the importance of the unit normal vector of a sphere in vector calculations, particularly in relation to the position vector. The unit normal vector, denoted as n hat, is essential because it is perpendicular to the sphere's surface, while the position vector, r, points from the center to a point on the sphere. The confusion arises from the difference between these vectors and their roles in calculations, particularly in flux integrals. A participant notes a discrepancy in their calculations of the vector field, mistakenly arriving at a different result than expected. The conversation highlights the significance of understanding the distinction between normal and position vectors in vector field analysis.
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I was looking at this example:

http://keep2.sjfc.edu/faculty/kgreen/vector/block3/flux/node10.html

and was confused between the difference between \hat{}n and \vec{}r

Why is the original vector field not given in terms of a unit vector? And what difference does this make?

Thanks :)
 
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Sorry that's supposed to be n hat and the vector r, I am a latex noob.
 
I also don't quite get why the is unit vector is not just r hat
 
"r", with the arrow over it is the "position vector" at a given point on the sphere. n with a hat is the unit vector in that direction. I presume they are using "n" to represent the unit vector because it is "normal" to the spherical surface and "n" is the standard notation for a normal vector.

For a sphere with center at the origin, the normal vector at any point is in the direction of the position vector. For any other surface that would not be true.
 
Thank you Ivy. Very helpful.
 
I got \vec{f}.\hat{n} as 1/r^{4} not 1/r^{2} as they got. What have I done wrong?
 
There is no "f" so I assume you mean "F" at the site linked to. That is defined by
\vec{F}= \frac{\vec{r}}{r^3}
\frac{\vec{r}}{r} is the unit vector \vec{n} normal to the sphere so the length of \vec{F} is 1/r^2. I don't know how you would have gotten 1/r^4.
 
I got it by doing:

\vec{F} . \hat{n} = \frac{\vec{r}}{r^{3}} .\frac{\vec{r}}{r} = \frac{1}{r^{4}}

I don't see what is wrong with that.
 
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