Why Is This Iterated Integral Expression a Homotopy Invariant?

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SUMMARY

The discussion centers on the homotopy invariance of the expression involving closed 1-forms, specifically the equation w1^w2 + dw12 = 0. The user seeks to understand why the iterated integral expression, represented as ∫w1w2 + ∫w12, remains invariant under smooth paths. The conclusion reached is that this expression is indeed a homotopy invariant, confirming the relationship between the integrals of the closed forms along the specified paths.

PREREQUISITES
  • Understanding of closed 1-forms in differential geometry
  • Familiarity with wedge products and their properties
  • Knowledge of homotopy theory and invariants
  • Basic concepts of smooth paths in calculus
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  • Explore the concept of homotopy invariance in algebraic topology
  • Learn about the applications of iterated integrals in mathematical analysis
  • Investigate the relationship between wedge products and homology
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lavinia
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I am trying to understand why the following expression is a homotopy invariant.

Start with 2 closed 1 forms whose wedge product is null homologous.

w1^w2 + dw12 = 0

I want to understand why

\int w_ {1}w_ {2} + \int w_ {12}

is a homotopy invariant of smooth paths where

\int w_{1}w_{2}

is the iterated integral of the two 1 forms along the path
 
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