- #1
- 32
- 0
f(x)=1+sinx
what am I doing wrong here?
1+sin(-x)= 1-sin(x)
what am I doing wrong here?
1+sin(-x)= 1-sin(x)
..then again if we look at f(x) = 1 + cosx we would see it is even, for
1 + cosx = 1 + cos(-x)
From this I would assume adding a constant to an even function yields no change, but adding a constant to an odd function makes it neither odd nor even.
I really don't know, perhaps someone can elaborate.