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f(x)=1+sinx
what am I doing wrong here?
1+sin(-x)= 1-sin(x)
what am I doing wrong here?
1+sin(-x)= 1-sin(x)
lendav_rott said:..then again if we look at f(x) = 1 + cosx we would see it is even, for
1 + cosx = 1 + cos(-x)
From this I would assume adding a constant to an even function yields no change, but adding a constant to an odd function makes it neither odd nor even.
I really don't know, perhaps someone can elaborate.
The reason for this is because the definition of an odd function is that f(-x) = -f(x) and the definition of an even function is that f(-x) = f(x). However, trigonometry functions do not follow these definitions, which is why they are neither odd nor even.
Yes, the sine function (sin(x)) is an example of a trigonometry function that is neither odd nor even. This is because sin(-x) = -sin(x), which is not the same as sin(x). Therefore, the sine function is neither odd nor even.
The graph of a trigonometry function that is neither odd nor even will not have any symmetry. It will not be symmetric about the origin (like an odd function) or symmetric about the y-axis (like an even function).
Yes, there are many real-world applications of trigonometry functions that are neither odd nor even. For example, the sine function is used in many applications such as sound and light waves, while the cosine function is used in applications such as architecture and engineering.
No, a trigonometry function cannot be both odd and even. By definition, a function can only be either odd or even, and not both. However, some trigonometry functions may have certain properties that make them behave like odd or even functions in certain cases.