Why is W(VI) more stable than Cr(VI)

  • Thread starter sludger13
  • Start date
  • #1
83
0

Main Question or Discussion Point

I'm not sure why Chromium(VI) is reducing and Tungsten(VI) isn't. I also noticed their radius is quite similar. Is that related?
 

Answers and Replies

  • #2
DrDu
Science Advisor
6,023
755
I think it is due to the d-orbitals in Cr being the first ones (3d) they don't have to be orthogonal to inner shells and are therefore relatively more strongly bound than 4d or 5d orbitals in the higher periods. Similar trends can be observed in the other groups, too, e.g. V vs. Nb or Ta, Fe vs Ru or Os.
 
  • #3
83
0
So the (3d) orbitals in Tungsten are potentially higher? Is it due to (s) orbitals core repulsion?
 
  • #4
DrDu
Science Advisor
6,023
755
Of course not the 3d orbitals in tungsten, but the 5d orbitals.
If you want to view this as the result of a repulsion, it is rather 3d and 4d Pauli repulsion.
 
  • #5
83
0
Ok, could you place here some links... because it's better if I read something for first. The only phenomenon I'm aware of is (ns) orbital energy fall due to Pauli repulsion, and obviously this isn't the entirely same thing.
 

Related Threads for: Why is W(VI) more stable than Cr(VI)

  • Last Post
Replies
3
Views
4K
  • Last Post
Replies
1
Views
7K
Replies
4
Views
2K
Replies
3
Views
13K
  • Last Post
Replies
3
Views
39K
Replies
1
Views
4K
Top