Why Isn't the Answer to the Hyperbolic Function e^10x?

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bobsmith76
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Homework Statement




Screenshot2012-02-08at22412AM.png


why is the answer not e^10x ?

If you ignore the e's it should be

5x - 5x + 5x - - 5x, or
5x - 5x + 5x + 5x, which is 10x
 
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If you ignored the e's, it wouldn't be a hyperbolic function, but a linear function.
 
well, i still don't see any reason why the answer is not e^10x
 
Hint:

[tex] e^{x} + e^{y} \neq e^{x + y}[/tex]

For example: Take [itex]x = y = 0[/itex] and compare the two sides of this unequality.
 
Bob, this is basically [itex]\frac{a+b}{2} + \frac{a-b}{2} = \frac{a}{2} + \frac{b}{2} + \frac{a}{2} - \frac{b}{2} = (2)(\frac{a}{2}) = a[/itex]. Simple algebra. Here [itex]a = e^{5x}[/itex] and [itex]b = e^{-5x}[/itex].

But your comment indicates a deeper confusion about exponents and algebraic principles. I would suggest that it might be a good idea to review basic algebra including the rules of exponentiation.