- #1
PRB147
- 127
- 0
Why the kink ([tex]\phi(x)=tanh(\frac{x}{\xi})[/tex]),
can not tunnel into vacuum [tex]+v [/tex]or [tex]-v[/tex] (Spontaneous symmetry breaking vacuum).
From the boundary condition([tex]x\rightarrow \pm\infty, \phi(x)\rightarrow \pm v[/tex]),
it is self-evident.
but the book states:
Due to the infinite high energy barrier, the kink can not tunnel into the vacuum.
where is the infinite high energy barrier?
The energy density is [tex]E(x)=\frac{gv^4}{2}sech^4 (\frac{x}{\xi})[/tex],
whose integration over all space is finite.
where is the infinite high energy barrier?
can not tunnel into vacuum [tex]+v [/tex]or [tex]-v[/tex] (Spontaneous symmetry breaking vacuum).
From the boundary condition([tex]x\rightarrow \pm\infty, \phi(x)\rightarrow \pm v[/tex]),
it is self-evident.
but the book states:
Due to the infinite high energy barrier, the kink can not tunnel into the vacuum.
where is the infinite high energy barrier?
The energy density is [tex]E(x)=\frac{gv^4}{2}sech^4 (\frac{x}{\xi})[/tex],
whose integration over all space is finite.
where is the infinite high energy barrier?