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Why maxwell's 3rd equations has no coefficient?

  1. Sep 21, 2014 #1
    For the four Maxwell equations, only the third one (Faraday's Law) has a proportionality coefficient of -1, while rest have a magnetic constant or electric constant .

    It doesn't seem like the units of the third law are calibrated to eliminate the constant. So why is the coefficient equal to exactly -1, not some materially dependent coefficient k?
  2. jcsd
  3. Sep 21, 2014 #2


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  4. Sep 21, 2014 #3


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    I second jasonRFs comment. It is purely due to the units chosen.
  5. Sep 22, 2014 #4

    Meir Achuz

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    The real question is, why do the other 3 equations have dimensional constants introduced. That is because they use different units for E and B, even though they are parts of the same tensor.
  6. Sep 22, 2014 #5

    Vanadium 50

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    But this is historical - like measuring distances and times in different units. Time should be measured in meters.
  7. Sep 24, 2014 #6
    This is the answer I am looking for.
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