Why pressure inside a liquid in different shaped vessels at

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Pressure in a liquid at a given depth is determined solely by the weight of the liquid above it, not by the shape or volume of the container. This means that in different shaped vessels, as long as the height of the liquid column is the same, the pressure at that depth will also be the same. The presence of walls or the shape of the vessel does not affect the pressure because it is a function of depth and density. Therefore, regardless of the container's design, the pressure at the same height remains consistent. Understanding this principle clarifies why pressure behaves uniformly in liquids across various vessel shapes.
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why pressure inside a liquid in different shaped vessels at same height same thought they are of different volumes and shapes?
 
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I really don't understand this question.
Could you rephrase it?
 
He's asking why pressure increases with depth in the same manner regardless of the shape of the container.
 
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rcgldr said:
He's asking why pressure increases with depth in the same manner regardless of the space of the container.
Yes.. Thats right..answer me please
 
future Einstein said:
why pressure inside a liquid in different shaped vessels at same height same thought they are of different volumes and shapes?
Why should it be different?
 
Why should it matter if there is a wall next to the water or just more water?

Or:

If pressure is equal to the weight of the water above (divided by area), why would it matter what is next to it?
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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