Why removal of other electrons cause binding energy increase

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SUMMARY

The discussion centers on the concept of the shielding effect in X-ray Photoelectron Spectroscopy (XPS) and its impact on binding energy. It is established that the removal of outer-shell electrons leads to an increase in binding energy due to reduced electron shielding. The attraction between the nucleus and inner-shell electrons is countered by the repulsion from outer-shell electrons, which can create confusion regarding the net effect on binding energy. Clarification is provided on how the removal of outer electrons allows inner electrons to experience a stronger nuclear attraction, thus increasing binding energy.

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  • X-ray Photoelectron Spectroscopy (XPS) fundamentals
  • Understanding of atomic structure and electron shells
  • Knowledge of chemical bonding and electron interactions
  • Basic principles of quantum mechanics related to electron behavior
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Chemists, material scientists, and researchers involved in surface analysis and spectroscopy who seek to understand the effects of electron interactions on binding energy in XPS measurements.

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I'm talking about the chemical shift.

In XPS test, oxidation leads to the increase of binding energy. This is determined by:
1. attraction between nuclear and the electron
2. shielding effect from outer-shell electrons

My question is :
What does shielding effect mean? Shield what? The positive charge in nuclear attract 1s electron. Also, 1s electron will be repelled by outer shell electrons. It seems both of these two forces have the same direction.

I'm a bit confused despite having understood this ... can anyone help?
 
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the nuclear attract electron with direction from outer to inner, and also, the outer-shield electron repels inner electron with the same direction. As a result, the inner electron will goes outer when outer electron removes, thus the binding energy seems to decrease.
I don't know where I'm wrong.
 

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