Why the door on door due to its weight is zero

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SUMMARY

The discussion centers on the concept of torque in relation to a door fixed by hinges, emphasizing that while there is a torque due to the door's weight, it is effectively zero in terms of rotational equilibrium. The participants clarify that the direction of the torque created by the door's weight does not lead to any net rotation about the hinge, thus maintaining equilibrium. This highlights the importance of understanding the relationship between torque direction and rotational motion in physics.

PREREQUISITES
  • Understanding of rotational equilibrium
  • Basic principles of torque and its calculation
  • Familiarity with hinge mechanics
  • Knowledge of weight distribution and its effects on objects
NEXT STEPS
  • Study the principles of rotational dynamics in physics
  • Learn about torque calculation methods and their applications
  • Explore the mechanics of hinges and their role in rotational systems
  • Investigate real-world examples of rotational equilibrium in engineering
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Physics students, mechanical engineers, and anyone interested in understanding the principles of torque and rotational equilibrium in everyday objects.

Rishisharma9058
The door fixed by hinges is in rotational equilibrium.Then why torque due to its weight is zero
 
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Rishisharma9058 said:
The door fixed by hinges is in rotational equilibrium.Then why torque due to its weight is zero
There is a torque due to its weight, but what is the direction of that torque? How does it relate to rotation about the hinge?
 

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