Why they chose maximum and not minimum functions

1. Jan 10, 2009

transgalactic

Last edited: Jan 10, 2009
2. Jan 10, 2009

HallsofIvy

Staff Emeritus
It's not clear what your question is. In the first example you give, they have $|x-a||x-b|< \epsilon$ in order to get |x-a| only, you have to divide both sides by |x-b| "inverting it reverses the inequality. That doesn't happen in the second example- there is no reciprocal.

3. Jan 10, 2009

transgalactic

when to use MAX when to use MIN ?