# I Why time in formula accelarion has exponent two

1. Sep 23, 2016

### edephysic

hello folks,

I am learning about how create a equation dimensional to formula Force (m*a).
I know this formula written this way:
[F]=[ma]
where:
m=mass
a=acceleration -> L/T²

The result is [F] = M * (L/T²) * L⁰
My result it's right?

Why T, relative time, has exponent two in formula acceleration?

Sorry about my English, I am learning this language :)
thanks

2. Sep 23, 2016

### Staff: Mentor

Recall that acceleration is a velocity ([L]/[T]) divided by time [T]. ([L]/[T])/[T] = [L]/[T2]

3. Sep 23, 2016

### edephysic

I think I understood.
It's the same: [L][T^-2]?

The formula referent equation dimensional it's right?
thanks

[UPDATE]
Therefore:
the formula relative equation dimensional is: [F] = [M][L][T^-2]?
I understood, the exponent two it is achieved through rule potentiation.

Last edited: Sep 23, 2016
4. Sep 23, 2016

### phinds

to expand a bit on what Doc Al said, look at it this way:

Velocity is rate per unit of time, or for example, distance per second.

Acceleration is THAT per second and since "THAT" is "distance per second" you have "(distance per second) per second" and we write that as (D/T)/T, or D/T2

5. Sep 23, 2016

### Staff: Mentor

Yes. 1/[T^2] = [T^(-2)]

Good.