1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Why time in formula accelarion has exponent two

  1. Sep 23, 2016 #1
    hello folks,

    I am learning about how create a equation dimensional to formula Force (m*a).
    I know this formula written this way:
    [F]=[ma]
    where:
    m=mass
    a=acceleration -> L/T²

    The result is [F] = M * (L/T²) * L⁰
    My result it's right?

    Why T, relative time, has exponent two in formula acceleration?

    Sorry about my English, I am learning this language :)
    thanks
     
  2. jcsd
  3. Sep 23, 2016 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Recall that acceleration is a velocity ([L]/[T]) divided by time [T]. ([L]/[T])/[T] = [L]/[T2]
     
  4. Sep 23, 2016 #3
    I think I understood.
    It's the same: [L][T^-2]?

    The formula referent equation dimensional it's right?
    thanks

    [UPDATE]
    Therefore:
    the formula relative equation dimensional is: [F] = [M][L][T^-2]?
    I understood, the exponent two it is achieved through rule potentiation.
     
    Last edited: Sep 23, 2016
  5. Sep 23, 2016 #4

    phinds

    User Avatar
    Gold Member
    2016 Award

    to expand a bit on what Doc Al said, look at it this way:

    Velocity is rate per unit of time, or for example, distance per second.

    Acceleration is THAT per second and since "THAT" is "distance per second" you have "(distance per second) per second" and we write that as (D/T)/T, or D/T2
     
  6. Sep 23, 2016 #5

    Doc Al

    User Avatar

    Staff: Mentor

    Yes. 1/[T^2] = [T^(-2)]

    Good.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted