Why why why? Sum of torque, changes in directions? This is

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Homework Help Overview

The discussion revolves around understanding the application of trigonometric functions in torque problems, specifically the confusion regarding the use of sine and cosine in relation to force components and angles in a torque diagram.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster expresses frustration over the alternating use of sine and cosine in torque calculations and questions the reasoning behind the assignment of these functions to specific components. Some participants suggest focusing on forming triangles to clarify the relationships between angles and sides, while others emphasize the importance of identifying the perpendicular component of the force in relation to the torque formula.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the formation of triangles to determine the appropriate trigonometric functions, but a clear consensus on the original poster's confusion has not yet been reached.

Contextual Notes

The original poster appears to be grappling with the application of trigonometric functions in a torque context, indicating a potential misunderstanding of how angles relate to force components in diagrams. There is also a suggestion to disregard axes in favor of triangle formation, which may reflect a common approach in resolving such issues.

riseofphoenix
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Why oh WHY do the arrows in this TORQUE problem keep alternating between SINE and COS

Number9.png

This is what they did:
Solution.png


I understand the whole Torque = F * r, but WHY (at the top of the diagram) is the arrow pointing up = (25 N)cos 30 and NOT sin and why is the arrow pointing to the right underneath it (25 N)sin 30 and not cos?? Same goes for the other arrows...I thought the x-axis (horizontal) was ALL COSINE and the y-axis (vertical) was SINE. This is so frustrating!
They keep doing this in ALL of their problems and it really confuses me.
They keep changing it from left to right...please help!
 
Last edited:
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Forget the axes. Form triangles with the angles and determine the trig functions for the sides of the triangles you are looking for
 


Review the definition of torque. If you write torque as F*r (where r is the distance from the axis to the point of application of the force), then F is the component of the force that acts perpendicular to r. Thus, the formula should be \tau = ##F_{\bot}\:r## where ##F_{\bot}## is the perpendicular component of the force.

[Edit: Ah, I think I misunderstood your difficulty. You are having trouble with finding the perpendicular component of the force. Follow PhizKid's advice! (You would use the cosine function for the x-component of a force only if the angle is measured from the x-axis.)]
 
Last edited:


PhizKid said:
Forget the axes. Form triangles with the angles and determine the trig functions for the sides of the triangles you are looking for

Ohhhh!
Ok.
Thanks!
 

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