Will NaOH dissolve aluminum without damaging fiberglass?

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    Aluminum Dissolve
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SUMMARY

The discussion centers on the chemical dissolution of aluminum, specifically 6063 aluminum tubes, while preserving fiberglass/epoxy coatings. Participants suggest using sodium hydroxide (NaOH) as an effective method for dissolving aluminum, noting that it does not significantly damage epoxy resins. Alternatives such as hydrochloric acid (HCl) and baking soda (NaHCO3) are also mentioned, with HCl being aggressive and NaHCO3 providing a slower, controlled reaction. The consensus is that NaOH is a viable choice, especially when the aluminum oxide layer is removed to enhance reactivity.

PREREQUISITES
  • Understanding of chemical reactions involving sodium hydroxide (NaOH)
  • Knowledge of aluminum types, specifically 6063 aluminum
  • Familiarity with fiberglass and epoxy materials
  • Basic principles of acid-base chemistry
NEXT STEPS
  • Research the effects of sodium hydroxide on various epoxy resins
  • Explore the use of hydrochloric acid in aluminum dissolution
  • Investigate the properties and applications of baking soda (NaHCO3) in etching aluminum
  • Learn about the safety protocols for handling caustic substances and acids
USEFUL FOR

This discussion is beneficial for chemists, materials engineers, and hobbyists involved in metalworking or restoration projects, particularly those seeking to dissolve aluminum without damaging surrounding materials.

  • #31
Borek said:
Compounds like aluminates are notoriously difficult to describe, as their composition - in terms of number of water molecules and OH- attached to the cation - is a matter of multistep equilibrium. Hence you will find different formulas in different sources.
Yes, this is true, but that one I've never seen it before.
 
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  • #32
lightarrow said:
Are you sure Na3AlO3 really exists? Anyway, I don't see any problem in the previous reaction you wrote:

2Al + 2NaOH + 2H2O ---> 2NaAlO2 + 3H2
+ ---
Hello, no I am not sure it exists ,but i don't have a problem with 3Na and AlO3
in solution.
The problem with the previous reaction i was having is that it implies that the hydrogens
in the two waters are reduced/released in the product as hydrogen gas.
And I could not see any mechanism for that in the reaction with NaOH and Al.
If you can describe that mechanism I would appreciate it
(please place the pos & negs over the ions)
 
  • #33
morrobay said:
+ ---
Hello, no I am not sure it exists ,but i don't have a problem with 3Na and AlO3
in solution.
The problem with the previous reaction i was having is that it implies that the hydrogens
in the two waters are reduced/released in the product as hydrogen gas.
And I could not see any mechanism for that in the reaction with NaOH and Al.
If you can describe that mechanism I would appreciate it
(please place the pos & negs over the ions)
Al reacts with water when the oxide layer is removed:

2Al + 3H2O --> Al2O3 + 3H2

NaOH dissolves the oxide layer.
 

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