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Will this circuit work as I predict it to?

  1. Jan 19, 2012 #1
    I want to design a basic Oscillator circuit with an NPN transistor.

    My predictions:

    When C1 charges up to 0.7 volts, it will open up the npn transistor and allow 3 v dc to flow to the LED. C1 is then discharged and the process repeats itself.

    My schematic:
    attachment.php?attachmentid=42862&stc=1&d=1327029240.png
     

    Attached Files:

  2. jcsd
  3. Jan 19, 2012 #2

    vk6kro

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    Science Advisor

    No, sorry, it won't do that.

    There is no reason the capacitor would discharge.

    The voltage across the capacitor rises to about 0.6 volts above the LED voltage and then the transistor turns on and the LED lights up.

    So, if the LED was a white one and it needed 3.5 volts to turn on, then the voltage across the capacitor would rise to about 3.5 volts + 0.6 volts or 4.1 volts.

    This voltage would then stay on the capacitor and the LED would light up.
     
  4. Jan 20, 2012 #3
  5. Jan 21, 2012 #4

    NascentOxygen

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    Staff: Mentor

    You need two transistors to make the basic multivibrator-type digital oscillator.
     
  6. Jan 21, 2012 #5

    vk6kro

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    There is a phase shift oscillator which gives a sine wave out, but it requires a very high gain transistor:
    Phase-shift_Oscillator.gif

    There is this one (below) which gives enough output to drive a speaker.

    http://dl.dropbox.com/u/4222062/NPN%20PNP%20OSC.PNG [Broken]

    The waveform shown is across the 8 ohm resistor which represents the speaker.
     
    Last edited by a moderator: May 5, 2017
  7. Jan 21, 2012 #6

    NascentOxygen

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    Staff: Mentor

    Make the 100kΩ resistor variable to vary the frequency.
     
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