WiMAX Transmitter: Can 1 EXAbit/sec be Transmitted?

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SUMMARY

The discussion centers on the feasibility of transmitting 1 EXAbit per second using WiMAX technology, which is capable of providing a 30 Mbit connection to users located 50 km away. The original poster incorrectly applies the inverse power law to estimate the necessary input power for such a transmission. A correction is provided, suggesting the use of the Friis transmission equation to accurately calculate received signal power and assess its viability against system noise.

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  • Understanding of WiMAX technology and its capabilities
  • Familiarity with the inverse power law in signal transmission
  • Knowledge of the Friis transmission equation
  • Basic concepts of signal-to-noise ratio in communication systems
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  • Research the Friis transmission equation for accurate signal power calculations
  • Explore the principles of signal-to-noise ratio in wireless communications
  • Investigate the limitations and capabilities of WiMAX technology
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Network engineers, telecommunications professionals, and anyone interested in understanding high-capacity data transmission technologies like WiMAX.

leonmate
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I was reading about WiMAX networks and how they can provide a 30mbit connection to a user 50km away!

Now, I don't have a great understanding of data transfer but I assume inverse power law applies??

Pf = Pi / 4*pi*r^2

At 50km

Pf = Pi / 10^10 * pi

For Pf = 30mbit/sec = 30*10^6
Pi must equal:

30*10^6 * 10^10 * pi = 10^18 bits/sec = 1 EXAbit/sec

Really?! Can they transmit an EXAbit of data per second? How the hell do these things work?!
 
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leonmate said:
I was reading about WiMAX networks and how they can provide a 30mbit connection to a user 50km away!

Now, I don't have a great understanding of data transfer but I assume inverse power law applies??

Pf = Pi / 4*pi*r^2

At 50km

Pf = Pi / 10^10 * pi

For Pf = 30mbit/sec = 30*10^6
Pi must equal:

30*10^6 * 10^10 * pi = 10^18 bits/sec = 1 EXAbit/sec

Really?! Can they transmit an EXAbit of data per second? How the hell do these things work?!
The calculation is incorrect. You need to look up the Friis formula on the Internet as a starting point. This will give the received signal power, and then you need to work out if it will compete with the noise of the system.
 

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