Work against the external pressure

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SUMMARY

The discussion centers on calculating the work done against external pressure during the reaction of nitrogen and hydrogen to form ammonia. The formula W = -PexΔV is identified as essential for this calculation, with Pex set at -1 atm (equivalent to -101,325 Pa). Participants highlight the need to determine the change in volume (ΔV) to proceed, suggesting the ideal gas law (PV = nRT) as a potential method to find the necessary volumes for the calculation. The reaction is confirmed to be exothermic, which may influence the volume change.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of chemical reaction stoichiometry
  • Familiarity with thermodynamics concepts, particularly work and pressure
  • Basic understanding of exothermic and endothermic reactions
NEXT STEPS
  • Calculate ΔV using the ideal gas law (PV = nRT) for the ammonia reaction
  • Explore the implications of exothermic reactions on gas volume changes
  • Investigate the relationship between pressure, volume, and work in thermodynamic processes
  • Review the concept of standard conditions for gas reactions (1 atm, 25°C)
USEFUL FOR

Chemistry students, chemical engineers, and anyone studying thermodynamics and reaction kinetics will benefit from this discussion.

omni
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in the picture you can see the reaction.

it's known that 2 mol nitrogen reaction with 6 mol hydrogen gas to create ammonia.
what is the work against the external pressure in 1 Atm in 25 degrees Celsius?

i think i need to use this formula:W=-PexdeltaV.
but i can't know what is deltaV.

i just know that -Pex=-1atm. 1atm=101,325 Pa
and is a exothermic reaction.

how can i keep on from here?

thanks.
 

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ΔV is just a volume change - what is an initial volume? What is a final volume?
 
Is not given in the description question.
maybe i can use PV=nRT?
and from this formula i can find V?

what are you think?
and just to be sure W is what i need to find yes?

thanks.
 

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