Work Done and final temperature of 5 mols of Ideal Gas

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Homework Help Overview

The discussion revolves around a problem involving the work done and final temperature of an ideal monatomic gas during expansion. The original poster presents a scenario where five moles of gas absorb heat and perform work, leading to a question about the final temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the work-energy relationship but encounters discrepancies in their calculations. Participants question the accuracy of the formula used and explore the relationship between internal energy and temperature for an ideal gas.

Discussion Status

Participants are actively engaging in clarifying concepts related to the internal energy of gases and its relation to temperature. Some guidance has been offered regarding the degrees of freedom for a monatomic gas, and there is an ongoing exploration of the correct application of formulas.

Contextual Notes

There is mention of potential errors in calculations and significant figures, as well as constraints related to the number of attempts allowed for submitting answers. The original poster expresses uncertainty about their previous successful application of the formula.

TFM
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[SOLVED] Work Done and final temperature of 5 mols of Ideal Gas

Homework Statement



Five moles of an ideal monatomic gas with an initial temperature of 129 degrees Celsius expand and, in the process, absorb an amount of heat equal to 1160 Joules and do an amount of work equal to 2020 Joules.

What is the final temperature of the gas?

Homework Equations



W = -nR(T_f - T_i)

The Attempt at a Solution



I have used the above formula before, and it worked then but doesn't appear to be working as well now

2020 - 1160 = -5*8.31(T_f - 129)

420 = -41.55(T_f - 129)

-10.1 = T_f - 129

T_f = -10.1 + 129

This gives me 118.9, which I have entered, and it says that:

" Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures. "

I have tried also 120 as well, with the same response!

I doubt its the formula, because I have used it before? Any Ideas?

TFM
 
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How does the internal energy of an ideal monoatomic gas relate to its temperature? (Your formula is not quite right.)
 
Would that be this:

U = \frac{1}{2}nRT per degree of Freedom.

?

TFM
 
Yes! And how many degrees of freedom are there?
 
There are three degrees of Freedom, since it is a monatomic gas.

TFM
 
Good. Now finish it up.
 
This would be:

U = \frac{3}{2}nRT

Can the T part be T = (Tf - Ti)

?

TFM
 
TFM said:
This would be:

U = \frac{3}{2}nRT
Yes.

Can the T part be T = (Tf - Ti)
If you rewrite the above equation in terms of changes in U and T (as you should), yes.
 
Would the change in U still be 420?

TFM
 
  • #10
I tried:

U = \frac{3}{2}nR(T_f - T_i)

and put in:

420 = \frac{3}{2}(5)(8.31)(T_f - 129)

IOt gave me an answer of 122, I put it in, And MP gas said itis wrong, and I have used up all my tries. Any ideas where I could have gone wrong?

TFM
 
  • #11
Arithmetic error: 1160 - 2020 = ?
 
  • #12
Drat! I put 2020 - 1600 into my calculator by mistake! Putting in 860, I get the final temperature to be 115

Thanks for the help, even if my sillyness cost me :rolleyes:,

TFM
 

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