- #1

clutch12

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## Homework Statement

Hey this is my first time on here and I'm kinda lost on what I am doing. Any help would be great and the question is

Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.18 MeV, where 1 mega electron volt is equal to 1*10^6 multiply (1.6*10^-19) joules. What is the separation of the protons from each other when they momentarily come to a stop?

## Homework Equations

Dont think i can type the equation

## The Attempt at a Solution

So i multiplied the initial kinetic energy by how much 1 electron vold is equal to and then multiplied it by the work

0.18 * 1*10^6 * 1.6* 10^-19

=2.88* 10^-14 J (kinetic energy of both protons)

Next i try to find the distance and this is where i have the trouble

2.88*10^-14 J = (9*10^9)(1.6*10^-19)^2/d

d= (9*10^9)(1.6*10^-19)^2 / 2.88*10^-14 J

d= 8 * 10^-15m