Work done by springs in a series

sillybean
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Homework Statement


Two springs, with force constants k1 and k2, are connected in series, as shown in the figure
Walker.7.68.jpg


How much work is required to stretch this system a distance x from the equilibrium position?

Homework Equations



W=1/2kx^2

The Attempt at a Solution



I have no idea how to derive this. I mean I've looked on the wikipedia article on hooke's law and figured that I just change the equation to W=1/2 (1/k1 + 1/k2)x^2

I'm guessing the problem with this is that the distances that the two stretch are not equal because of the different spring constants but I don't know how to go about showing this in an equation.
 
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is that 1/(2kx^2) or (1/2k)x^2
 
it is (1/2k)x^2
 
using 1/kt=1/k1+1/k2. Substitute into elastic potential energy equation.

Edit: forget that... Misunderstood your question I think.
 
Last edited:
i did that
W=1/2 (1/k1 + 1/k2)x^2

and this was wrong
 
sillybean said:
i did that
W=1/2 (1/k1 + 1/k2)x^2

and this was wrong

I know. That'd why I edited and said forget it, Lol.
 
ah i see. so any other takers.
 
still need help. is my theory about distances being different right?
 

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