Work done on a moving square wire loop in a B-field

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Discussion Overview

The discussion revolves around the work done on a moving square wire loop in a magnetic field, exploring concepts related to electromotive force, current, and the forces acting on charges within the wire. Participants examine the implications of changing magnetic fields and the conditions under which work is done, with references to Faraday's law and Ohm's law.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Meta-discussion

Main Points Raised

  • One participant states that while the Ampere's force exerts a force on charges in the wire, it does no work on them, as they would move in circular motion without the wire.
  • Another participant argues that as the loop moves, a changing magnetic field induces a non-zero electric field, suggesting that work is done.
  • A different participant claims that if the loop moves in a homogeneous magnetic field, no work is done, as it moves with constant velocity.
  • One participant provides a detailed analysis involving the induced electromotive force and the resulting current, concluding that the work done is due to ohmic losses in the wire rather than the magnetic field itself.
  • Several participants express frustration over changes made to the original question, emphasizing the importance of maintaining the integrity of the discussion for clarity.

Areas of Agreement / Disagreement

Participants do not reach consensus on whether work is done on the wire loop. Some argue that work is done due to induced currents and ohmic losses, while others maintain that no work is done if the magnetic field is constant.

Contextual Notes

Participants reference specific conditions such as the presence or absence of a changing magnetic field and the implications of constant velocity motion, which may affect the conclusions drawn about work done.

feynman1
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1590754268483.png

There’s a current i in the loop in the figure. The Ampere’s force iLB on a wire of length L exerts on charges in the wire but it does no work on the charges. The charges would go in circular motion if there were no wire. Then the wire exerts exactly iLB on those charges to keep the charges moving at constant speed. Then likewise the charges exert iLB on the wire. Then it is the charges that are doing work iLBv on the wire?
 

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As the loop moves to the right on both the right and left sides there is a large ##\partial \vec B/\partial t## and therefore by Faraday’s law we get a non zero ##\vec E## field.
 
Dale said:
As the loop moves to the right on both the right and left sides there is a large ##\partial \vec B/\partial t## and therefore by Faraday’s law we get a non zero ##\vec E## field.
i changed that pic so that there's no change in B
 
feynman1 said:
i changed that pic so that there's no change in B
You can change the pic, but now your pic doesn’t represent reality. If there is no change in the magnetic field then the wire cannot be carrying current.
 
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I don't know, whether I read your drawing correctly: If the entire loop moves in a homogeneous magnetic field there's indeed no work done. It just moves with constant velocity.

The usual setup is shown here in the figure with the resistor (the explanations on the webpage are not optimal, to say it friendly):

http://labman.phys.utk.edu/phys222core/modules/m5/motional_emf.html

Take the situation in this figure as the initial condition and let the wire just run without any external force. Then we can make a simple analysis to see how work is done here. We use the quasistationary approximation.

The motion of the wire induces an electromotive force according to Faraday's Law (in SI units)
$$\mathcal{E}=-\dot{\Phi}=v B d.$$
According to Ohm's law this induces a current going upwards in the wire
$$i=\mathcal{E}/R=v B d/R.$$
Now due to this current there acts a force to left on the wire, i.e.,
$$m \dot{v}=-B i d=-\frac{B^2 d^2}{R} v.$$
The power is
$$P=m \dot{v} v = -\frac{B^2 d^2}{R} v^2.$$
This is precisely the heat due to the ohmic losses in the wire,
$$P_\text{ohm}=R i^2=\frac{B^2 d^2}{R} v^2.$$
So the work done here is due to friction of the charges in the wire. It's not the magnetic field directly doing any work. It cannot do work, because the force on each charge is always perpendicular to its velocity.
 
It's pretty obnoxious to ask a question, get an answer, and then change the question by editing it. That just confuses everybody.

As pointed out, there's no work done. If you draw the system at two different times, nothing changes: you could take two snapshots and overlay them so the loops are in the same place and there is otherwise no difference.
 
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feynman1 said:
i changed that pic so that there's no change in B

Vanadium 50 said:
It's pretty obnoxious to ask a question, get an answer, and then change the question by editing it. That just confuses everybody.
@Vanadium 50 is right. @feynman1, the correct way to do it is to add a new post with the correction and not edit the original, especially after getting an answer.
 
how to delete the original post
 
feynman1 said:
how to delete the original post
You don't. I don't think you see the point here.

The original post #1 asks a question. An answer #2 is provided. If you then edit or delete #1, then #2 looks silly and hard to explain. It would be unfair to the author of #2.

Instead.
The original post #1 asks a question. An answer #2 is provided. You post a modified question #3. Someone provides an answer #4. Now the whole thread #1, #2, #3, #4 can be read in sequence and understood. It becomes part of our archives for other students to find and to read in the future.
 
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anorlunda said:
You don't. I don't think you see the point here.

The original post #1 asks a question. An answer #2 is provided. If you then edit or delete #1, then #2 looks silly and hard to explain. It would be unfair to the author of #2.

Instead.
The original post #1 asks a question. An answer #2 is provided. You post a modified question #3. Someone provides an answer #4. Now the whole thread #1, #2, #3, #4 can be read in sequence and understood. It becomes part of our archives for other students to find and to read in the future.
i made a mistake in the original post, so don't see any sense keeping it. but if you want, i'll create another one.
 

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