- #1
TJDF
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Homework Statement
There is a pulley system, identical to system (ii) in the following image:
http://www.phys.unsw.edu.au/~jw/graphics/blocks1.GIF
A 1.24 kg canister hangs from one pulley, you are lifting with constant speed, what is the work you do while lifting the canister 1.60 cm and a force 6.08 N?
Homework Equations
W = F x D (displacement) x Cos theta (where theta is the angle between work and displacement
The Attempt at a Solution
I originally just plugged in my values into the formula and yielded -0.09728 J. When I got it wrong I did a little looking around and tried both multiplying and dividing by 2. Here are all my attempts: 0.0486 J, -0.0486 J, -0.09728 J, 0 J, 0.09728 J, 379.75 J, 0.218 J, -0.218 J