Work Energy Theorem in Spring Block System

AI Thread Summary
In a vertical spring-block system undergoing simple harmonic motion (SHM), the Work-Energy Theorem can be applied by considering the work done by gravity. It is often simpler to analyze the net force, which combines both the spring force and gravitational force, along with the net potential energy. Applying the theorem from the relaxed length of the spring rather than the equilibrium position can simplify calculations. Including all forces—gravity, spring force, and kinetic energy—provides a clearer understanding of the system. The discussion concludes with a confirmation of clarity on the application of the theorem.
SDewan
Messages
32
Reaction score
1
Just got confused that while applying the Work - Energy Theorem in a vertical Spring-Block system performing SHM (considering no other external forces other than gravity), when I apply the theorem from equilibrium position, do I consider the work done by gravity?
 
Physics news on Phys.org
Hello SD, :welcome:

In principle: yes.
In exercises it's often easier to work with the net force (i.e. the vector sum of the spring force and the gravitational force) and the associated net potential energy ##{1\over 2} kx^2## where ##x## is the extension minus the equilibrium extension.

If you want this clearer, you may want to provide a complete problem statement for the exercise that confused you.
 
Yea I understood that it will be better to apply the W-E Principle from the relaxed length of the spring, rather than the equilibrium position.
I feel that it is simpler to take all forces into consideration. i.e. gravity, spring force and the kinetic energy.
I have got the clarity, thanks a ton!
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top