1. The problem statement, all variables and given/known data A crate of mass 10.0 kg is pulled up a rough incline with an initial speed of 1.5 m/s. The pulling force is 100 N parallel to the incline which makes an angle of 20.0° with the horizontal. The coefficient of kinetic friction is .4 and the cart is pulled 5.00 m. e) What is the speed of the crate after being pulled 5.00m? 2. Relevant equations Delta Energy Mechanical = -Force_friction(d) + Work_external K_f + U_f = K_i + U_i - Force_friction(d) + Work_external For constant Force and parallel force and displacement: W = F(d) 3. The attempt at a solution K_f + U_f = K_i + U_i - Force_friction(d) + Work_external .5mvf2 + mgh = .5mvi2 + 0 - Force_friction(d) + Work_external h = 5sin(20°) Force_friction = -μ Fn = -μ 98cos(20°) Work External = F(d) = 100N * 5m = 500J .5mvf2 + mgh = .5mvi2 +μ 98cos(20°)(5) + 500 vf2 = (.5mvi2 +μ 98cos(20°)(5) + 500 - mgh) / (.5m) v = 10.27 m/s The answer is given as 5.65 m/s. Any help is appreciated!