Work & Energy: When to Use PE vs KE?

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SUMMARY

The discussion clarifies the conditions under which work is equated to potential energy (PE) versus kinetic energy (KE) in physics problems. Specifically, when analyzing a scenario involving a 55.8 kg person running up a 12.0 m hillside inclined at 25.0°, the work done is set equal to the change in potential energy rather than kinetic energy. This is because the person's speed remains constant, resulting in no change in kinetic energy. Therefore, the work done is solely attributed to the increase in potential energy as the individual ascends the hill.

PREREQUISITES
  • Understanding of basic physics concepts, specifically work, potential energy, and kinetic energy.
  • Familiarity with the equations for calculating work, PE, and KE.
  • Knowledge of vector components in physics, particularly in relation to inclined planes.
  • Ability to analyze energy conservation in mechanical systems.
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems.
  • Learn how to calculate potential energy using the formula PE = mgh.
  • Explore the relationship between work and energy in various physical scenarios.
  • Investigate the concept of average power output in physics problems.
USEFUL FOR

Students studying physics, educators teaching energy concepts, and anyone seeking to deepen their understanding of work-energy principles in mechanical systems.

LexRunner
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I have been studying the Work and Energy chapter of physics and am currently confused on when to make work equal potential energy and when to make it equal to change in kinetic energy. Some of the problems have the work equal to change in KE and some have it equal to PE.
For example, why is work in this problem,
"Calculate the average power output necessary for a 55.8 kg person to run up a 12.0 m long hillside, which is inclined at 25.0° above the horizontal, in 3.00 s. Express your answer in horsepower"
set to equal PE rather than KE?
 
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The total change in energy is going to be zero.
If the energy change of what you are looking at is not zero - then some energy was added or removed from it.
That is the work.

This could be a change in kinetic energy, in potential energy, or a bit of both.
At your level - either kinetic energy or potential energy will be changing. Just work out which one.

In your example - it implied by the wording that the kinetic energy has not changed ... the person is running at the same speed at the top of the hill as at the bottom. Thus the change in kinetic energy is zero - contributing nothing to the calculation.
 

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