Work in a PV Curve: Is the Work Done 0?

  • Thread starter Thread starter gabdolce
  • Start date Start date
  • Tags Tags
    Curve Work
AI Thread Summary
In a closed thermodynamic cycle, the work done is represented by the area enclosed by the Pressure-Volume curve. While it may seem that the work done is zero since the system returns to its initial state, this is not always the case. If the work from state 1 to state 2 is significantly greater than the work from state 2 back to state 1, the cycle can produce net work. This situation typically arises when the system experiences different loads at various points in the cycle. Thus, a closed cycle can indeed perform work despite returning to its original state.
gabdolce
Messages
6
Reaction score
0
Hey all,

In one of my textbooks, there is a passage in the thermodynamics section that states that:

For a closed cycle where the system returns to its initial state, the work done is the area enclosed by the curve (when looking at a Pressure-Volume graph).

Shouldn't the work done by this process be a total of 0 instead?

Thanks in advance.
 
Physics news on Phys.org
Not necessarily. A closed cycle can do work. Suppose it cycles between two states. If the work done getting from state 1 to state 2 is much larger than the work done (with the opposite sign of course) from state 2 back to state 1, the cycle will do net work. Note that this does require the system to be under a different load during different parts of the cycle. This changing load is what allows the system to end at the same state that it started while still doing work.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?

Similar threads

Back
Top