Is work a function of state in adiabatic processes?

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SUMMARY

In adiabatic processes, where heat transfer (Q) is zero, the internal energy change is equal to the work done on the system. While internal energy is a function of state, work is not typically considered a function of state because it depends on the path taken to reach a given state. However, in an adiabatic process, the work done can be well-defined, leading to the question of whether it can be classified as a function of state. The discussion concludes that even in adiabatic processes, work remains path-dependent and thus is not a function of state.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with concepts of internal energy and work
  • Knowledge of adiabatic processes in thermodynamics
  • Basic grasp of state functions in thermodynamic systems
NEXT STEPS
  • Study the implications of the first law of thermodynamics in various processes
  • Explore the differences between adiabatic and non-adiabatic processes
  • Learn about state functions and path functions in thermodynamics
  • Investigate real-world applications of adiabatic processes in engineering
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Students of thermodynamics, engineers working with heat transfer systems, and anyone interested in the principles of energy transfer in physical systems.

eprparadox
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I'm reading a thermo book and I'm on the chapter dealing with the first law of thermodynamics. The book is discussing functions of state and how the internal energy is a function of state because it has a well defined value at every equilibrium state of the system.

It says that the work and heat are not functions of state because if we look at a given state, we wouldn't be able to tell how the energy was added or subtracted from the heat or work in order to achieve our current total internal energy.

My question is: in an adiabatic process, where Q = 0, the internal energy is just equal to the work done on the system. In this case, would work now be a function of state along with the internal energy since the work would be well defined always?

Thanks!
 
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eprparadox said:
I'm reading a thermo book and I'm on the chapter dealing with the first law of thermodynamics. The book is discussing functions of state and how the internal energy is a function of state because it has a well defined value at every equilibrium state of the system.

It says that the work and heat are not functions of state because if we look at a given state, we wouldn't be able to tell how the energy was added or subtracted from the heat or work in order to achieve our current total internal energy.

My question is: in an adiabatic process, where Q = 0, the internal energy is just equal to the work done on the system. In this case, would work now be a function of state along with the internal energy since the work would be well defined always?

Thanks!
Suppose you had another process path (non-adiabatic) that took you to the exact same final state. Would the work be the same? Certainly, the change in internal energy would be the same. This is what we mean when we say something is a function of state.
 

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