Work, Kinetic energy, and power question

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SUMMARY

The discussion focuses on calculating the average power, force, and speed of protons in a linear accelerator designed for a master's degree physics project. The kinetic energy of each proton is specified as 11.3 keV, and the mass of a proton is 1.67 x 10-27 kg. The accelerator must deliver 1.00 x 109 protons per second over a distance of 1.80 meters. Key equations utilized include the work-kinetic energy theorem and the power equation P = Fv.

PREREQUISITES
  • Understanding of kinetic energy and its relation to work
  • Familiarity with the work formula: Work = Force x Distance
  • Knowledge of power calculations: Power = Force x Velocity
  • Basic concepts of particle physics, specifically regarding protons
NEXT STEPS
  • Calculate the average power required using the formula P = E/t, where E is energy and t is time
  • Determine the force applied to each proton using the equation F = KE/d
  • Find the final speed of each proton using the kinetic energy formula KE = 1/2 mv2
  • Explore the implications of energy transmission in particle accelerators
USEFUL FOR

Physics students, particularly those studying particle physics or working on accelerator design projects, as well as educators seeking to understand practical applications of kinetic energy and power calculations.

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Homework Statement



To complete your master's degree in physics, your advisor has you design a small, linear accelerator capable of emitting protons, each with a kinetic energy of 11.3 keV. (The mass of a single proton is 1.67*10^(-27) kg.) In addition, 1.00*10^9 protons per second must reach the target at the end of the 1.80-m-long accelerator.

(a) What the average power must be delivered to the stream of protons?
_____μW

(b) What force (assumed constant) must be applied to each proton?
______ N

(c) What speed does each proton attain just before it strikes the target, assuming the protons start from rest?
_______ m/s

Homework Equations



Work - kinetic energy theorem
Work formula


The Attempt at a Solution



Ok so I said KE= Work total or KE=Fd. I have all of those to get the force for question 2, then plug it into my power equation P=Fv for number 1 then W=1/2mv^2 for number 3... but I'm all mixed up on the units... so any help on that would be great
 
Physics news on Phys.org
1 proton has 11.3eV and you have 1(10^9) protons/second, so in 1 second how much energy do 1(10^9) protons transmit?
 

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