- #1

bbhill

- 6

- 0

**Given the cone, z^2=x^2+y^2 z<= 1 filled with water, find the work needed to flip the cone upside down.**

**W = Fd**

**Well, I figured I could integrate the force along the distance (0,1) by multiplying the distance from 0 times the cross section circle area times the density. That would give me the force of the cone, but then I would need to find the distance each infinitesimally small cross section would have to be displaced to flip the cone and I've gotten lost there.**