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Work needed to flip cone upside down.

  1. Nov 22, 2009 #1
    Given the cone, z^2=x^2+y^2 z<= 1 filled with water, find the work needed to flip the cone upside down.



    W = Fd



    Well, I figured I could integrate the force along the distance (0,1) by multiplying the distance from 0 times the cross section circle area times the density. That would give me the force of the cone, but then I would need to find the distance each infinitesimally small cross section would have to be displaced to flip the cone and I've gotten lost there.
     
  2. jcsd
  3. Nov 22, 2009 #2

    Dick

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    You'll find it a lot easier to use potential energy for this problem. Can you find the potential energy of the original cone and then the potential energy of the flipped cone?
     
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