Work of isothermal compression at constant pressure

Click For Summary
SUMMARY

The discussion focuses on the calculation of work (W), heat (Q), and internal energy change (ΔU) for a 1.80 mol sample of an ideal gas undergoing isothermal compression from 58.1 L to 15.6 L at a constant external pressure of 2.72 atm. The correct formula for work is W = -PΔV, resulting in W = -115.6 liter-atm. Since the process is isothermal, the change in internal energy ΔU equals zero, as the temperature remains constant. The participant, Colton, seeks assistance in confirming these calculations before a submission deadline.

PREREQUISITES
  • Understanding of ideal gas laws
  • Familiarity with thermodynamic concepts such as isothermal processes
  • Knowledge of work calculations in thermodynamics
  • Basic proficiency in unit conversions (liter-atm to Joules)
NEXT STEPS
  • Review the ideal gas law and its applications in thermodynamics
  • Study the derivation and implications of the first law of thermodynamics
  • Learn about the relationship between work and heat in isothermal processes
  • Explore unit conversion techniques for thermodynamic calculations
USEFUL FOR

This discussion is beneficial for students in thermodynamics, chemistry enthusiasts, and anyone involved in gas law applications or preparing for exams in physical chemistry.

ColtonCM
Messages
33
Reaction score
2
The Problem:

A 1.80 mol sample of an ideal gas is compressed isothermally from 58.1 L to 15.6 L using a constant external pressure of 2.72 atm .

Calculate W:

Calculate Q:

Calculate ΔU:

Attempt at solution:

I tried W = P(ΔV) to no effect, W = nRTln[Vf/Vi] to no effect. The online submission form tells me if the sign is wrong so I know that the numbers I got from these two equations are not correct as if they were and the sign was wrong it would have told me. I used 273K as T since T is not given.

Any help would be appreciated. Due at midnight and friends have all remained oddly out of contact.

I can't go for Q and U until I figure out the first part.

Thanks,

Colton
 
Science news on Phys.org
Well, if the external force per unit area is held constant at 2.72 atm, the work should be PΔV = -115.6 liter-atm. What units do they want the answer in?

If the initial and final temperatures of an ideal gas are the same (isothermal), what is ΔU?

Chet
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
533
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
9
Views
32K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K