Working out internal resistance.

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SUMMARY

The discussion focuses on calculating the internal resistance of a cell using the equation 0.8(5+r)=1.2(2.5+r). Participants emphasize the importance of applying the distributive property to simplify the equation. By expanding both sides, users can isolate the variable 'r' to find the internal resistance. This method is straightforward and essential for solving similar electrical circuit problems.

PREREQUISITES
  • Understanding of basic algebraic manipulation
  • Familiarity with electrical circuit concepts
  • Knowledge of the distributive property in mathematics
  • Experience with solving equations for unknown variables
NEXT STEPS
  • Practice solving equations involving internal resistance in circuits
  • Explore the application of Ohm's Law in circuit analysis
  • Learn about series and parallel circuit configurations
  • Investigate the impact of internal resistance on battery performance
USEFUL FOR

Students studying electrical engineering, hobbyists working on circuit projects, and anyone interested in understanding battery characteristics and internal resistance calculations.

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I have two different circuits and I need to work out the internal resistance of the cell.

So far I have got to 0.8(5+r)=1.2(2.5+r)

Where do I go from here?
 
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Assuming the equation you have is correct, it should be relatively simple to solve. I suppose the simplest way to get you started is to suggest using the distributive property on both sides of your equation in order to "clean it up."
 
he means multiply out yer brackets ;)
 

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