Let f(x)=x^2/(1-x^2 ) a) Find f'(x) b) Find f"(x) For the answer to a) they give f'(x)=2x/〖(1-x^2)〗^2 and for b) f"(x)=2 (1+〖3x〗^2)/〖(1-x^2)〗^3 Now after many rounds of trying i have not been able to get an answer remotely close to what they have given. i don;t know if it is due to me over working a simple problem or what. the same applies to b), taking the second derivative. For a) i applied the quotient rule: f(x)=x^2/(1-x^2 ) f'(x)=(2x(1-x^2)-(1-x^2)x^2)/(1-x^2)^2 then it stops there as i don't know where to proceed, i am not entirely sure if what i have done is correct but other methods result in something similar. Then for b) f'(x)=2x/〖(1-x^2)〗^2 Using their answer and trying to work with it to see if i fared any better for the 2nd derivative proved that i was lost. any help with a) would be appreciated as it means i could work out b) and any similar problems in the future.