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a) Find f'(x)

b) Find f"(x)

For the answer to a) they give f'(x)=2x/〖(1-x^2)〗^2

and for b) f"(x)=2 (1+〖3x〗^2)/〖(1-x^2)〗^3

Now after many rounds of trying i have not been able to get an answer remotely close to what they have given. i don;t know if it is due to me over working a simple problem or what. the same applies to b), taking the second derivative.

For a) i applied the quotient rule:

f(x)=x^2/(1-x^2 )

f'(x)=(2x(1-x^2)-(1-x^2)x^2)/(1-x^2)^2

then it stops there as i don't know where to proceed, i am not entirely sure if what i have done is correct but other methods result in something similar.

Then for b)

f'(x)=2x/〖(1-x^2)〗^2

Using their answer and trying to work with it to see if i fared any better for the 2nd derivative proved that i was lost. any help with a) would be appreciated as it means i could work out b) and any similar problems in the future.