World's hardest easy problem

  • Thread starter namanjain
  • Start date

Answers and Replies

  • #2
97
3
I haven't the solution, I get the equation x + y = 130, where x and y are angles. If [itex] x, y \in Z^+[/itex]
This is a diophantine equation. We know: x, y > 0. y > x. And y is greater than 90 degrees.
the most probable angles:
[itex] x=20^o\,\, ,y=110^o[/itex]
or
[itex] x=30^o\,\, ,y=100^o[/itex]
 
Last edited:
  • #3
reenmachine
Gold Member
513
8
I tried a couple of things but didn't solve it yet , but there's probably a way to build your way up to the x angle using the tricks in my sketch (just don't have the patience to construct the triangles properly and doing it now):
 

Attachments

Last edited:
  • #4
Integral
Staff Emeritus
Science Advisor
Gold Member
7,201
56
Simple geometry is all that is required.

Why can't you do this for yourself? Don't give up so easy.
 
  • #5
70
0
diophantine equation
wazz it,
i tried it hard thats why asking askin solution,
well i need an approach
i asked it to one of my faculty at coaching and he straightaway said it's wrong so i needed to check
 
  • #6
70
0
I haven't the solution, I get the equation x + y = 130, where x and y are angles. If [itex] x, y \in Z^+[/itex]
This is a diophantine equation. We know: x, y > 0. y > x. And y is greater than 90 degrees.
the most probable angles:
[itex] x=20^o\,\, ,y=110^o[/itex]
or
[itex] x=30^o\,\, ,y=100^o[/itex]
I tried a couple of things but didn't solve it yet , but there's probably a way to build your way up to the x angle using the tricks in my sketch (just don't have the patience to construct the triangles properly and doing it now):
whatss y in equation
x+y= 130

reenmachine i agree myself i even not have patience and doing it (doing angle sum property question) , thanks for tip of parallel lines but what benefit it does
 
  • #7
reenmachine
Gold Member
513
8
reenmachine i agree myself i even not have patience and doing it (doing angle sum property question) , thanks for tip of parallel lines but what benefit it does
I don't know since I didn't solve it.It was just a suggestion of strategy to attack the problem , maybe it's a dead end , but the parallel lines will at least allow you to chase more angles , whether or not they end up being useful to find angle x.

If you don't have the patience to try it , I suggest you do not ask others to do it for you as it's not recommended on the forum to ask for answers without showing that you tried hard before hand.I'm not a moderator , just friendly advice.Also , saying that you tried hard is not showing that you tried hard.
 
Last edited:
  • #8
70
0
till here i ve done (in attchment)
one of image is inverted
so i did the mirror image from webcam toy
 

Attachments

  • #9
reenmachine
Gold Member
513
8
You should draw the triangles/angles to scale if you want to try that strategy.

It should look like the picture below
 

Attachments

Last edited:
  • #10
70
0
from the original figure below, y seems equal angle bde

http://thinkzone.wlonk.com/mathfun/triangle.htm [Broken]
=====
where x + y + 50 = 180
however i got that but i also meant that diophtine (whatever is name) equation

well where is it taught
 
Last edited by a moderator:
  • #11
70
0
you should draw the triangles/angles to scale if you want to try that strategy.

It should look like the picture below
does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for me
though i think i'll print that page
 
  • #12
70
0
Uff! After long work with a correct precise figure i bored and saw solution on one of other web pages

is it bad of me not getting it (i'm 15 yrs and preparing rmo and iit)
 
  • #13
reenmachine
Gold Member
513
8
does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for me
though i think i'll print that page
I don't know , you should listen to your teachers before you listen to me that's for sure :tongue2:

You should also listen to mentors here as they are qualified to help you.
 
Last edited:
  • Like
Likes 1 person
  • #14
reenmachine
Gold Member
513
8
Might try to prove both of these triangles (or another pair of triangles) are similar to prove x = 20 :
 

Attachments

Last edited:

Related Threads on World's hardest easy problem

  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
6
Views
2K
  • Last Post
Replies
6
Views
4K
  • Last Post
Replies
17
Views
12K
  • Last Post
3
Replies
58
Views
35K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
1
Views
1K
Replies
18
Views
3K
Replies
3
Views
2K
Top