I haven't the solution, I get the equation x + y = 130, where x and y are angles. If [itex] x, y \in Z^+[/itex]
This is a diophantine equation. We know: x, y > 0. y > x. And y is greater than 90 degrees.
the most probable angles:
[itex] x=20^o\,\, ,y=110^o[/itex]
[itex] x=30^o\,\, ,y=100^o[/itex]
whatss y in equationI tried a couple of things but didn't solve it yet , but there's probably a way to build your way up to the x angle using the tricks in my sketch (just don't have the patience to construct the triangles properly and doing it now):
I don't know since I didn't solve it.It was just a suggestion of strategy to attack the problem , maybe it's a dead end , but the parallel lines will at least allow you to chase more angles , whether or not they end up being useful to find angle x.reenmachine i agree myself i even not have patience and doing it (doing angle sum property question) , thanks for tip of parallel lines but what benefit it does
however i got that but i also meant that diophtine (whatever is name) equationfrom the original figure below, y seems equal angle bde
where x + y + 50 = 180
does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for meyou should draw the triangles/angles to scale if you want to try that strategy.
It should look like the picture below
I don't know , you should listen to your teachers before you listen to me that's for sure :tongue2:does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for me
though i think i'll print that page