Writing out chemical equations

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SUMMARY

The discussion focuses on writing balanced chemical equations for the reactions of chromium with sulfur and bismuth with oxygen. The correct balanced equation for the reaction of chromium and sulfur is Cr + 3S → Cr2S3, indicating that two chromium atoms react with three sulfur atoms. For the bismuth and oxygen reaction, the balanced equation is 4Bi + 3O2 → 2Bi2O3, where bismuth typically exhibits a +3 oxidation state and oxygen forms O2- ions. The importance of understanding oxidation states and the correct representation of ionic charges is emphasized throughout the discussion.

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  • Familiarity with balancing chemical equations
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  • Learn about oxidation states and their significance in reactions
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Homework Statement



Write a balanced equation for:

1. the reaction of chromium with sulfur

2. the reaction of bismuth with oxygen


Homework Equations



Chromium is a transition metal and sulfur has a 2- charge.

The Attempt at a Solution



For the first one, I'm thinking that since sulfur has a 2- then chromium must have a 2+ charge so it would form a product of CrS. I thought it would just be Cr + S ----> CrS

That's before balancing of course but that's not the answer either. It's supposed to be Cr + S ----> Cr2S3 (before balancing)

Why are there subscripts?

The second one makes absolutely no sense to me because O is 2- and Bi is I believe 3-.
 
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Chromium is most commonly found in the +3 oxidation state.

Have you heard of covalent bonding?

Also, the way in which you refer to O as being "2-" etc. is incorrect. An atom is electrically neutral. What you actually mean is that oxygen tends to form O2- ions.
 
Bismuth - like chromium - likes +3, Bi3+.
 

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