- #1
franky2727
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i get that a unit vector is U/modU but how would it be written for example 8i-4j-8k would it be simply (8i-4j-8k)/144?
Writing Unit Vectors: A Quick Guide for Scientists
- Thread starter franky2727
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- Unit Unit vector Vector
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Homework Help Overview
The discussion revolves around the concept of unit vectors in vector notation, specifically focusing on how to express a given vector in unit form. The subject area pertains to vector mathematics and normalization.
Discussion Character
- Conceptual clarification, Mathematical reasoning
Approaches and Questions Raised
- Participants explore the correct notation for unit vectors, questioning whether the expression of a vector should be split into its component parts. There is also discussion about the proper normalization process and the representation of the vector.
Discussion Status
Participants have provided various representations of the normalized vector and have engaged in clarifying the notation. There are multiple interpretations of how to express the unit vector, and while some participants suggest different forms, there is no explicit consensus on a single preferred method.
Contextual Notes
Some participants note corrections regarding the normalization process, specifically addressing the use of square roots in the denominator. There is also a playful tone in the suggestions for expressing the vector, indicating a casual exploration of the topic.
- #2
CompuChip
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Notation for the normalized vector [itex]\vec u[/itex] is also [itex]\hat u[/itex]. Note, that it is [itex]\vec u / ||\vec u||[/itex] and not [itex]\vec u / || \vec u ||^2[/itex].
- #3
franky2727
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ah sorry i ment over root 144 . apart from that is the way i wrote it fine or would i have to split it into I J and K parts?
- #4
CompuChip
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It doesn't matter;
(8i-4j-8k)/12 = (8/12) i - (4/12) j - (8/12) k.
(8i-4j-8k)/12 = (8/12) i - (4/12) j - (8/12) k.
- #5
HallsofIvy
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Or even better (2/3)i- (1/3)j- (2/3)kCompuChip said:
- #6
CompuChip
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HallsofIvy said:Or even better (2/3)i- (1/3)j- (2/3)k
Which is then again equivalent to
(2i - j - 2k) / 3
or
2(i - 1/2 j - k) / 3
Take your pick (or make your own :D)
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