X-Ray photon/wavelength question

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SUMMARY

The discussion revolves around calculating the wavelength of an X-ray photon emitted when a fast-moving electron collides with steel, resulting in an energy of 7.90×10-16 J. The key equations involved are E=hf for energy and frequency, and v=fλ for wave speed and wavelength. The correct frequency calculation is achieved by dividing the energy by Planck's Constant (h = 6.626×10-34 J·s), leading to a frequency of approximately 1.19×1018 Hz. The final wavelength is calculated to be 2.521×10-9 m, or 2,521 nm, confirming the calculations are accurate.

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  • Understanding of photon energy and wavelength relationships
  • Familiarity with Planck's Constant (h = 6.626×10-34 J·s)
  • Basic knowledge of wave equations (v = fλ)
  • Ability to perform scientific notation calculations
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Students in physics, educators teaching electromagnetic theory, and professionals in fields involving X-ray technology and quantum mechanics will benefit from this discussion.

Moomba44
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This is one of the questions on my regular worksheets we have before our tests:

A fast-moving electron traveling through a vacuum tube slams into a piece of steel, coming abruptly to rest and emitting an X-ray photon with an energy of 7.90×10-16 J. What is the wavelength of the photon?

I know I have to find the frequency and speed of the photon in order to find the wavelength. The problem is I do not know how to find either of the two (I had a long day at work so I'm pretty sure I'm just having a brain fart right now). If someone could help point me in the right direction it would be more than appreciated!
 
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Photons always travel at 3x10^8 m/s, the speed of light.
 
For a photon:
E=hf
E=Energy of the photon
h=Planck's Constant
f=Frequency

and of course for any wave v=f \lambda, and like Pengwuin said in the case of photons your velocity is about 3x108 m/s
 
Edit: Thank you dav, I thought I was on the right track but you confirmed it. Thanks a bunch guys!
 
Okay, I think I had better post again, because something is surely off in what I am doing with this problem. My answer that I got for Frequency was something in the neighborhood of 1.16x10^-50 s, and whenever I plug that into the wavelength equation and solve for wavelength I get the astronomical number of 2.58x10^58 cm/s.

Am I doing this problem right and should be getting a number that high? Or am I off in some of my calculations?
 
Look at the E=hf equation more carefully... I think you multiplied instead of divided.

Also keep in mind that wavelength has dimensions of length.
 
to find f I've been putting in f = E/h, which I've been imputting as the energy from the original problem, 7.9 x 10^-16, divided by h, so it looks like 7.9 x 10^-16/6.626 x 10^-34. Is this wrong right here or is my calculator possibly giving me funky numbers for no reason? lol.
 
\frac {7.9 \cdot 10^{-16}(J)}{6.626 \cdot 10^{-34}(J \cdot s)} gives me a frequency of 1.19 \cdot 10^{18} (\frac {1}{s}).
 
Last edited:
yeah, I realized i was putting something wrong into the equation, so for wavelength I got .252 cm...which corresponds to 2,520,000 nanometers...is this close to being right or am I still screwing something up?
 
  • #10
You divided 3x108m/s by 1.19x1018 1/s and got .00252 meters?

Check your calculations.
 
  • #11
Okay, I redid everything and I got 2.521x10^-9 m for the wavelength...I might as well take baby steps since either I or my calculator is screwing up what I type, so is this calculation correct? And if so, to convert it to nanometers I'm supposed to divide by 10^-9 if I'm not mistaken.
 

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