Y to Δ transformation of a circuit

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Homework Help Overview

The discussion revolves around the Y to Δ transformation in circuit analysis, specifically focusing on finding the currents i0 and ix in a given circuit configuration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the transformation process and the identification of nodes where resistors connect. There are attempts to clarify which resistors are involved in the Y configuration and how they relate to the currents in question.

Discussion Status

The conversation is ongoing, with participants providing guidance on identifying the correct resistors for the transformation. There is a focus on clarifying misunderstandings about the circuit layout and the connections between components.

Contextual Notes

Some participants express uncertainty about the circuit's configuration, noting that the orientation of components may affect their understanding of the Y to Δ transformation. There is an emphasis on the importance of recognizing connections rather than relying solely on visual representation.

sevag00
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Homework Statement



Use Y to Δ transformation to find i0 and i/x
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Homework Equations





The Attempt at a Solution



Here's my transformation.
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Calculated i0, which is equal to 3A.
I have no clue how to find ix.
 
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You'll need to find another "Y" to transform that leaves the Ix branch alone... Look for another point where three resistors come together at a node.
 
I can't find any. The others are all deltas.
 
sevag00 said:
I can't find any. The others are all deltas.

That's not true! Three resistors come together at the bottom node, too. Remember, the particular orientation of parts and wires on a circuit drawing is not important. What is important is what is connected to what. The Y in "Y" configuration may look more like an ω if you bend the wires around a bit...
 
Sorry, still no clue.
 
sevag00 said:
Sorry, still no clue.

Bottom central connection is the center of the Y. Three resistors leave that connection point. They are the 'arms' of the Y.
 
Do you mean the 12 ohm resistor that i0 passes through, the bottom 4 ohm resistor and the 4 ohm resistor that ix passes?
 
sevag00 said:
Do you mean the 12 ohm resistor that i0 passes through, the bottom 4 ohm resistor and the 4 ohm resistor that ix passes?

Yes, yes, no. Does the 4 Ω resistor that Ix passes through connect to the bottom node with the others?
 
Hmm. Then it should be the other 4 ohm resistor.
 

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