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Y to Δ transformation of a circuit

  1. Oct 30, 2013 #1
    1. The problem statement, all variables and given/known data

    Use Y to Δ transformation to find i0 and i/x
    Capture.jpg

    2. Relevant equations



    3. The attempt at a solution

    Here's my transformation.
    Untitled.jpg

    Calculated i0, which is equal to 3A.
    I have no clue how to find ix.
     
  2. jcsd
  3. Oct 30, 2013 #2

    gneill

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    Staff: Mentor

    You'll need to find another "Y" to transform that leaves the Ix branch alone... Look for another point where three resistors come together at a node.
     
  4. Oct 30, 2013 #3
    I can't find any. The others are all deltas.
     
  5. Oct 31, 2013 #4

    gneill

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    Staff: Mentor

    That's not true! Three resistors come together at the bottom node, too. Remember, the particular orientation of parts and wires on a circuit drawing is not important. What is important is what is connected to what. The Y in "Y" configuration may look more like an ω if you bend the wires around a bit...
     
  6. Oct 31, 2013 #5
    Sorry, still no clue.
     
  7. Oct 31, 2013 #6

    gneill

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    Staff: Mentor

    Bottom central connection is the center of the Y. Three resistors leave that connection point. They are the 'arms' of the Y.
     
  8. Oct 31, 2013 #7
    Do you mean the 12 ohm resistor that i0 passes through, the bottom 4 ohm resistor and the 4 ohm resistor that ix passes?
     
  9. Oct 31, 2013 #8

    gneill

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    Staff: Mentor

    Yes, yes, no. Does the 4 Ω resistor that Ix passes through connect to the bottom node with the others?
     
  10. Oct 31, 2013 #9
    Hmm. Then it should be the other 4 ohm resistor.
     
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