Y''(x) + A sin(y(x)) - B = 0; A,B : positive, real

  • Context: Graduate 
  • Thread starter Thread starter tarquinius
  • Start date Start date
  • Tags Tags
    Positive
Click For Summary
SUMMARY

The differential equation y''(x) + A sin(y(x)) - B = 0, with positive real constants A and B, is addressed in this discussion. The initial conditions provided are y(0) = 0 and y'(0) = 0. The transformation of the equation leads to the expression y'² = 2A cos(y) + 2B y + 2C, which indicates that the solution cannot be expressed in terms of a finite number of standard functions. The final form of the equation suggests that numerical methods or qualitative analysis may be necessary for further exploration.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with initial value problems
  • Knowledge of trigonometric functions and their properties
  • Basic skills in numerical methods for solving differential equations
NEXT STEPS
  • Explore numerical methods for solving nonlinear differential equations
  • Learn about phase plane analysis for second-order systems
  • Investigate the use of the Runge-Kutta method for initial value problems
  • Study the implications of energy conservation in mechanical systems
USEFUL FOR

Mathematicians, physicists, and engineers dealing with nonlinear dynamics and differential equations, particularly those interested in initial value problems and numerical solutions.

tarquinius
Messages
11
Reaction score
0
Hello there,

I have no idea how to solve the differential equation

y''(x) + A sin(y(x)) - B = 0 ,

where A and B are positive real numbers. I do also have initial conditions: y(0) = 0 and y'(0) = 0.

I would be grateful for any help.
 
Physics news on Phys.org
y''+A sin(y)-B=0
y''y'+A sin(y)y'-B y'=0
y'²/2-A cos(y)-B y =C
y'²=2A cos(y)+2B y +2C
dy/dx =y' = (+or-)sqrt(2A cos(y)+2B y+2C)
dx=(+or-) dy/sqrt(2A cos(y)+2B y+2C)
x =(+or-) integal (dy/sqrt(2A cos(y)+2B y+2C)) +c
cannot be expressed with a finit number of usual functions;
 
Thank you very much.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
558
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
8K