Young's double slit experiment with two sets of slits

Click For Summary

Homework Help Overview

The discussion revolves around Young's double slit experiment, specifically focusing on the conditions for interference minima and the implications of diffraction through slits. Participants are examining the relationships between variables in the context of wave interference and diffraction patterns.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • One participant attempts to derive a formula for the distance between slits based on the condition for interference minima, while another questions the appropriateness of starting with that condition, suggesting that diffraction should be considered first. There are also discussions about the correctness of the formula used for minima.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the relevance of diffraction in the context of the experiment, but there is no explicit consensus on the correct approach or formula at this stage.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or reference. There is also a focus on verifying the accuracy of the formulas being applied in the context of the problem.

Apashanka das
Messages
32
Reaction score
0
1. The problem statement, all variables and given/known da
15187116671331187855915.jpg
15187116671331187855915.jpg

Homework Equations


Interference minima is asinΘ=nλ/2 where n=1,3,5,7...
[/B]

The Attempt at a Solution


Putting ab/(2sqrt(b^2/4+d^2))=λ/2 for first order minima
And solving for d I get (b/2)*sqrt((2a/λ)^2-1) in which only the 2 factor differs in front of a in the square root
from the correct ans which is option 2 in the question
I may be wrong but where I didn't get it?
 

Attachments

  • 15187116671331187855915.jpg
    15187116671331187855915.jpg
    24 KB · Views: 1,094
Physics news on Phys.org
Why did you start with the condition for interference minima? The passage of light through the first slit is diffraction.
 
Apashanka das said:
1. The problem statement, all variables and given/known daView attachment 220386 View attachment 220386

Homework Equations


Interference minima is asinΘ=nλ/2 where n=1,3,5,7...
[/B]
Check the formula in red.
 
ehild said:
Check the formula in red.
yes I have used this formula
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
4K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
8K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K