Young's modulus and compression

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SUMMARY

The discussion centers on the analysis of forces acting on a rod positioned between shims A and B under compression, specifically examining the relationship between forces Fa, Fb, and F. The assertion that F + Fb = Fa is identified as incorrect, leading to implications regarding the center of mass and linear acceleration of the rod. The conversation highlights the necessity of understanding net forces and their impact on the structural integrity of the rod, particularly under applied forces at point R.

PREREQUISITES
  • Understanding of Young's modulus and its application in material science.
  • Familiarity with static equilibrium and net force concepts.
  • Knowledge of linear acceleration and its relation to force and mass.
  • Basic principles of mechanics, particularly in relation to forces acting on rigid bodies.
NEXT STEPS
  • Study the principles of Young's modulus in material deformation.
  • Learn about static equilibrium conditions and their applications in engineering.
  • Investigate the effects of net force on the motion of rigid bodies.
  • Explore the relationship between force, mass, and acceleration through Newton's laws.
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in structural analysis or material science will benefit from this discussion, particularly those interested in the behavior of materials under load.

LCSphysicist
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Homework Statement
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Relevant Equations
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See this figure:
1594196274703.png


The rod is put at first between A and B shims without comprehension, suddenly a force is applied at R from an axis as the figure points. Find Fa and Fb. (the figure is a look from above)

This can be solved by consider the "constant elastic" of the shims equal, but my discussion is another.

The immediately wrong affirmation that F + Fb = Fa, if we try to apply this, it will lead us to wrong answers.
I am trying to analyse the consequences of this, this implies that immediately the center of mass is not at zero net force, so it has linear acceleration (it could be found, if we knew the mass), but this is a little tricky, that is, at what stage the forces net force will be zero? Or is this, or the rod will broken some time later the figure.
 
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LCSphysicist said:
affirmation that F + Fb = Fa
Surely there is a force at "fixo"
 

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