The discussion focuses on calculating Young's Modulus for a nylon rope with a length of 21 m and a diameter of 1.4 cm. The correct formula for the cross-sectional area, assuming a circular cross-section, is πr², where the radius must be converted to standard units. The radius of the rope is 0.7 cm, which must be converted to meters for the final calculation of the area in m². Participants emphasize the importance of unit consistency in calculations.
PREREQUISITESStudents in physics or engineering courses, material scientists, and anyone involved in mechanical design or analysis of materials.
Assuming that it has a circular cross-section (a reasonable assumption), then the area would be that of a circle (\pi r^2). But be sure to use standard units for the radius.kiwikahuna said:Would the cross sectional area be the area: pi(0.7)^2
kiwikahuna said:Homework Statement
I'm working on a problem that is asking me to find Young's Modulus. I have the right formula and everything that I need but I can't seem to figure out how to find the cross sectional area of a nylon rope. The rope is 21 m long and 1.4 cm in diameter.
Homework Equations
The Attempt at a Solution
Would the cross sectional area be the area: pi(0.7)^2