Young's modulus of copper by projecting a laser

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SUMMARY

The discussion centers on an experiment conducted to determine the Young's modulus of copper using a laser projection technique. The lab instructor clarified that the use of a meter stick does not compromise the precision of the experiment, as the stress is determined by the force-to-area ratio (S=F/A), where a smaller area results in higher stress. Participants sought further clarification on how the meter stick's involvement could potentially affect precision, indicating a need for deeper understanding of the relationship between stress and measurement tools in experimental physics.

PREREQUISITES
  • Understanding of Young's modulus and its significance in material science.
  • Familiarity with the concept of stress and the formula S=F/A.
  • Basic knowledge of experimental physics and measurement techniques.
  • Experience with laser projection methods in laboratory settings.
NEXT STEPS
  • Research the principles of Young's modulus and its applications in materials engineering.
  • Explore the relationship between stress, force, and area in greater detail.
  • Investigate advanced measurement techniques in experimental physics, including laser projection methods.
  • Watch the recommended lecture on Young's modulus for visual and conceptual reinforcement.
USEFUL FOR

Students and educators in physics, materials scientists, and laboratory technicians involved in experimental design and measurement accuracy.

negat1ve
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Not really a problem but a concept I am having trouble understanding and I was hoping someone can explain to me better.

We performed an experiment in lab last week on finding the Young's modulus of copper by projecting a laser on the wall to magnify the effect of the change in length of the wire.

Our lab instructor told us that the precision of the experiment is NOT ruined from using a meter stick because that stress determines the order of magnitude. And that a small area means a huge stress cause of the relationship S=F/A.

Can someone please explain this to me better why the experiment is not ruined from using the meter stick. I am still a little confused. Thanks a lot!
 
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Not sure I understand exactly what you are confused about.

You might find this lecture useful however:

https://www.youtube.com/watch?v=YrRP-oGPjvk
 
It unclear to me too where the "meter stick" comes into play. Can you describe the experiment and also explain why one might have thought the meter stick would cause a loss of precision?
 

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