Young's Modulus of Pressure Sensor

[ptar]

Homework Statement

Here's the question, verbatim;
We want to build a pressure using a block of elastic material, where the pressure applied to the top surface is measured by a strain gauge mounted on one of the side walls of the block. The gauge factor of the strain gauge is 2.5. When 1 mm Hg of pressure is applied to the top surface, we obtain a delta R/R of 0.01% on the strain gauge. The nominal resistance of the strain gauge is 1000 Ohm.
(a) What is Young's Modulus of Elasticity (E) for the elastic block?

Homework Equations

Young's Modulus= Stress/ Strain = (F/A) / (delta l/l)

The Attempt at a Solution

Here the strain can also be given by the formula ((1/F) x delt.R/R), where F is the gauge factor. Plugging numbers in here, I've worked out the strain to be 4 x 10^-5. However, I have no idea what to do next. I'm sure you need area to work out stress. Or would integrating the pressure work, as pressure is dF/dA? But then you would still be left with a variable in the stress result.

Please help! Thanks.

 

[mathewmakil]

I have this same problem for my assignment and am stuck. I've found out the strain but no idea on working out the stress.

Homework Statement

Here's the question, verbatim;
We want to build a pressure using a block of elastic material, where the pressure applied to the top surface is measured by a strain gauge mounted on one of the side walls of the block. The gauge factor of the strain gauge is 2.5. When 1 mm Hg of pressure is applied to the top surface, we obtain a delta R/R of 0.01% on the strain gauge. The nominal resistance of the strain gauge is 1000 Ohm.
(a) What is Young's Modulus of Elasticity (E) for the elastic block?

Homework Equations

Young's Modulus= Stress/ Strain = (F/A) / (delta l/l)

The Attempt at a Solution

Here the strain can also be given by the formula ((1/F) x delt.R/R), where F is the gauge factor. Plugging numbers in here, I've worked out the strain to be 4 x 10^-5. However, I have no idea what to do next. I'm sure you need area to work out stress. Or would integrating the pressure work, as pressure is dF/dA? But then you would still be left with a variable in the stress result.

Please help! Thanks.