If I was to try to work this out I would use the Chinese Remainder Theorem and since 10557 = 3^3 . 17 . 23(adsbygoogle = window.adsbygoogle || []).push({});

end up with (Z/10557Z)* isomorphic to (Z/27Z)* x (Z/17Z)* x (Z/23Z)* isomorphic to C18 x C16 x C22 where Cn represents the Cyclic group order n.

How would I then write this as Cn1 x Cn2 x Cn3 s.t. n1 divides n2 divides n3?

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# (Z/10557Z)* as Abelian Groups

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