E=mc^2 proof. Why use Newtonian kinetic energy?

SamRoss
Gold Member
Messages
256
Reaction score
36
E=mc^2 proof. Why use Newtonian kinetic energy?

In "Does the Inertia of a Body Depend Upon its Energy-Content?" Einstein says that the difference in kinetic energy of a body before and after it releases some energy is...

K(0)-K(1)=E(gamma-1)

In his previous paper, he worked out the kinetic energy of masses as...

K=mc2(gamma-1)

Can't we immediately compare the two equations and conclude that E=mc^2? Why does Einstein bother converting the first equation above into

K(0)-K(1)=(1/2)(E/c2)v2

? It seems to me that this is a less precise method since he had to neglect magnitudes of fourth and higher order to get it.

**I know that me writing out gamma looks really dumb but I was having trouble with Latex.
 
Last edited:
Physics news on Phys.org


SamRoss said:
In his previous paper, he worked out the kinetic energy of masses as...
K=mc2(gamma-1)
Wait, are you sure about this? I don't think he derives this until the "Does the inertia..." paper.

SamRoss said:
Why does Einstein bother converting the first equation above into

K(0)-K(1)=(1/2)(E/c2)v2

? It seems to me that this is a less precise method since he had to neglect magnitudes of fourth and higher order to get it.
This is a good question. I was just puzzling over the same thing myself. I think it's because he wants to make contact with his audience's knowledge of the Newtonian theory, and also because he's about to propose some experimental tests. For example, if you measure the inertia of some radium salts before and after decay, you're doing it under completely Newtonian conditions, i.e., the sample is not moving at speeds comparable to c, so any higher-order corrections aren't negligible.

SamRoss said:
**I know that me writing out gamma looks really dumb but I was having trouble with Latex.
Here is how to write that: K=mc^2(\gamma-1). To see how I did that, click on the Quote button on my post. Sometimes it shows up after you submit your post without rendering the math, but if you reload the page it will render correctly. Other people will always see it rendered correctly.
 


bcrowell said:
Wait, are you sure about this? I don't think he derives this until the "Does the inertia..." paper.

I often look at the book "The Principle of Relativity" from Dover Publications, which is just a reprinting of a lot of original papers on the subject. Assuming the reprintings are accurate, Einstein derives the kinetic energy formula in section 10 of "On the Electrodynamics of Moving Bodies".

bcrowell said:
I think it's because he wants to make contact with his audience's knowledge of the Newtonian theory, and also because he's about to propose some experimental tests.

Yeah, that makes a lot of sense. "Does the Inertia" came out only shortly after "Electrodynamics". Einstein might not have felt confident that his own kinetic energy formula would have been accepted by his audience. His audience might not have even seen the formula if they hadn't read his other paper. Thanks for the insight.
 


SamRoss said:
I often look at the book "The Principle of Relativity" from Dover Publications, which is just a reprinting of a lot of original papers on the subject. Assuming the reprintings are accurate, Einstein derives the kinetic energy formula in section 10 of "On the Electrodynamics of Moving Bodies".

I see. That's interesting. So in "On the electrodynamics..." he proves it by calculating work, and in "Does the inertia..." he derives it in a completely different way. There are some remarks about the definition of force in "On the electrodynamics..." (including footnote 9) that show that he feels the whole thing is problematic.
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...

Similar threads

Back
Top