How to figure out the amount of heat (joules) needed to melt 1g of ice?

AI Thread Summary
To determine the heat required to melt 1g of ice, the key concept is the latent heat of fusion, which for water is 334 J/g. This means that to melt 1 gram of ice, 334 joules of energy are needed. The specific heat capacity of water, mentioned as 4.18 J/g°C, is not applicable for this calculation since it pertains to temperature changes rather than phase changes. The process of melting ice occurs at a constant temperature, requiring energy input without a temperature increase. Therefore, the correct answer is 334 joules for melting 1 gram of ice.
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So, first day of school today, and I'm in honors chemistry. I got a packet with refernce tables etc. and a homework assignment designed just to get you to use the tables and be able to connect one thing they say with another. Anyway, one question is "How much heat is required to melt 1g of ice?" I'm guessing by "how much", it's indicating that joules would be the proper unit to answer in, and the tables say that water has a specific heat capacity of 4.18 J/g times degrees celcius. My initial guess would just be 4.18 joules, but I've no real idea, can anyone explain how I'd go about figuring this out?
 
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Don't forget the latent heat of fusion.
 
Uhh...
Dude, I'm a junior in high school, besides learning the formulas for respiration and photosynthesis last year in bio, I have no real experience in chemistry at all, you completely lost me...
 
You said you got a packet with reference tables. Take a look and see if it has something called "latent heat of fusion."

Basically, it takes energy to melt ice and while the transition between solid and liquid is taking place the temperature remains constant. That energy is called the heat of fusion.

If that still doesn't help then maybe your teacher is only trying to see how much you know about chemistry by giving problems ranging from simple to advanced.
 
Tide said:
You said you got a packet with reference tables. Take a look and see if it has something called "latent heat of fusion."

Basically, it takes energy to melt ice and while the transition between solid and liquid is taking place the temperature remains constant. That energy is called the heat of fusion.

If that still doesn't help then maybe your teacher is only trying to see how much you know about chemistry by giving problems ranging from simple to advanced.
Alright...

It shows that with water, the heat of fusion is 334J/g, so that's the answer?
 
Multiply that number by 1 g and you get 334 Joules. :-)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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