
#1
Feb2608, 08:45 AM

P: 2

Hi, i would be grateful if anyone could help.
When using a lathe to cut a spindle of 10mm diameter at a cutting speed of 45m/min, how would i convert the 45m/min into rev/min and rad/s? Also how would i covert the cutting speed of 45m/min into mm/s for a spinde of 7mm? Thanks 



#2
Feb2608, 11:54 AM

P: 1,130

So, the spindle is 10 mm diameter. The circumference is thus 31 mm or 0.031m which is 0.031 m/revolution. Then 45 m/min divided by 0.031 m/revolution gives 1450 rpm. Note that, as your tool goes into the spindle, the surface speed will decrease as the diameter.




#3
Feb2608, 12:07 PM

Sci Advisor
P: 5,095

This question is posed rather strangely. The 45 m/min looks like a feed rate. It appears that the OP needs a depth of cut number. I'm probably misunderstanding the problem.




#4
Feb2608, 01:08 PM

Sci Advisor
HW Helper
P: 2,538

Chuck speed of a lathe1 revolution=2 [itex]\pi[/itex] radians 1 diameter = 2 radians 1 minute = 60 seconds 1 meter = 1000 millimeters Now, in this problem 1 diameter = 10 mm So  to get from meters per minute to revolutions per second: 45 meters/minute * (1 minute/60 seconds) * (1000 milimeters/1 meter) * (1 diameter/10 millimeters) * (2 radians/1 diameter) * (1 revolution/ 2 [itex]\pi[/itex] radians) Each of the fractions is 1, and you should be able to cross off the units. Regrouping gives... (45 * 1000 * 2) revolution / (60*10*2 [itex]\pi[/itex]) seconds. 



#5
Feb2608, 01:19 PM

P: 1,130




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