Initial Value Problem

by newtomath
Tags: initial
 HW Helper P: 1,583 I think that you were helped with the complimentary solution, for the particular integral I would try the function $f(t)=At^{4}+Bt^{3}+Ct^{2}+Dt +E +Fe^{t}$
 Math Emeritus Sci Advisor Thanks PF Gold P: 39,691 I have no clue what you mean by "Y1" and "Y2". Three independent solutions to the associated homogeneous equation are y1(t)=1, $y2(t)= e^t$, and $y3(t)= e^{2t}$. Normally, with a "right side" of t, you would try $At+ B$ but since t is already a solution, you should try $At^2+ Bt$. Normally with $e^t$ on the right side, you sould try $Ce^t$ but since $e^t$ is already a solution, you should try $Cte^t$. hunt_mat usually gives very good responses but he may have been overly sleepy here. I can see no reason to include third or fourth power and certainly no reason to combine "x" and "t"!