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Inverse Trig Function: Find Derivative of the Function 
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#1
Jan1912, 10:38 PM

P: 38

1. The problem statement, all variables and given/known data
find the derivative of the function f(x)=arcsec(4x) 2. Relevant equations I think this is a Relevant equations. d/dx[arcsecu]=u'/(u(√u^{2}1) 3. The attempt at a solution f'(x)=4/(4(√4^{2}1) =1/√15 I keep getting wrong in my online homework why? 


#2
Jan1912, 10:48 PM

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#3
Jan2012, 03:07 PM

P: 38

is it 4/(4x(√4x^{2}1))
I keep getting it wrong 


#4
Jan2012, 03:20 PM

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Inverse Trig Function: Find Derivative of the Function
What is u in your original integral? What is [itex]u^2[/itex]?



#5
Jan2012, 03:25 PM

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#6
Jan2012, 03:27 PM

P: 38

I mean this one (4x)^2



#7
Jan2012, 03:32 PM

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#8
Jan2012, 03:43 PM

P: 38

okay how about this answer??
f'(x)=arcsec4x+ 4/(4x(√(16x)^{2}1) 


#9
Jan2012, 03:49 PM

P: 38

I did this one in my homework online and it keeps saying I'm wrong



#10
Jan2012, 03:52 PM

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#11
Jan2012, 03:54 PM

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#12
Jan2012, 03:57 PM

P: 38

YAY it finally worked thank you :D



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